X(x+3)=x^2+x+20

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Solution for X(x+3)=x^2+x+20 equation: 



X(X+3)=X^2+X+20

We move all terms to the left:

X(X+3)-(X^2+X+20)=0

We multiply parentheses

X^2+3X-(X^2+X+20)=0

We get rid of parentheses

X^2-X^2+3X-X-20=0

We add all the numbers together, and all the variables

2X-20=0

We move all terms containing X to the left, all other terms to the right

2X=20

X=20/2

X=10

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